Autism test: If you cannot solve this simple math problem, then you have autism.
x-(30-x)
>>711950021
There isn't enough information to get a numerical value for x
15sqrt(2) = x
28,46
>>711950021
Does AE=CF?
>>711951157
yes
route of 27
>>711950909
There is plenty of information, you autist.
>>711951134
It asked for an exact value.
>>711950021
x = (30sqr) - (FCsqr)
Sqrt 810
sorry was wrong
>>711950021
x = 3*sqrt(3)
26
>>711950021
9*squrt(10)
>>711951411
that's already the right answer
>>711951733
Please explain
You need to know the measure of an angle
x^2 = sqrt (30^2 * 9 / 10)
x = sqrt 810
>>711951910
Angle DCF = 90 degrees
Top kek
>>711951949
i meant
squrt (x^2) = sqrt (30^2 * 9 / 10)
>>711952052
uff typing is pain today
120
>>711950021
That's backwards. Autists should have an easier time doing math than normal people.
>>711952052
sqrt x^2???
>>711952140
shhh....
let OP feel smart and special
each diagonal line is the same length as the outer ones
sqrt (x^2) is x
>>711951733
Since the square's sides are cut symmetrically by E and F in 1/3rd parts, FC is equal 1/3x.
So:
30 = 1/3x * x
90 = x^2
x = sqrt(90)
x = 9.49
>>711950909
It's a square, you nerd virgin
>>711951134
>>711951317
The exact value is sqrt(810) = 9*sqrt(10)
>>711950021
all right
AE = 3AB
let AB = alpha
so alpha² +(1/3aplha)² = 30²
10/9*alpha² = 900
alpha² = 810
alpha = sqrt(810) = x
4√6
Because the values of the known lines are the same and in a square, Line FC is 1/3 of x.
Using the Pythagorean theorem yields
(x)^2 + (x/3)^2 = 30^2
x^2 + x^2/9 = 900
(10/9)(x^2) = 900
x^2 = 810
x = sqrt(810)
>>711950021
>square
>length
x = AB
>>711952314
ups, it's ofc:
30^2 = (1/3x)^2 * x^2
>>711952465
How can we be sure AE = 3AB
since it's a square from the beginning
you take the lower triangle
one side 30
second side x
third side 1/3 * x (because it's divided evenly)
after that it's all phytagoras
30^2 = (1/3 * x)^2 + x^2
900 = 10/9 * x^2
810 = x^2
28,46 = x
(are we doing your math homework and you are to afraid say you aren't able to do it on your own?)
>>711952563
Man... I hate math
>>711952710
pythagoras
(have i mentioned typing is pain today?)
>>711952710
But there's no information informing AE is 1/3x
>>711952630
because math, the square is made of six congruent triangles
>>711952835
Man... I still hate math
>>711952834
it has to be because all lines in the box are the same length
>>711952945
evenly in a way 1/3 and 2/3
9*SQRT(10)
45
>>711953139
that's more or less the same like 28,46
>>711952834
triangles!
>>711953267
Yeah I see it now... Honestly I'm destined to fail math
>>711953267
i still think that we are doing his homework...
>>711951763
You can use the Pythagorean theorem to solve right angles.
Because the angles are all the same length (30), and they split the square 3 times, you can assume that lines AE and FC are 1/3 the length of x, so they are x/3.
Now for the math...
x^2+(x/3)^2 = 30^2
Simplifying this gives you this:
(10/9)x^2 = 900
Now divide both sides by 10/9
x^2=810
Square root it all and your done
x= √810
it's 3√3. simplify your expressions kiddos. here's a proof:
https://www.cymath.com/answer.php?q=x%5E2%2B(x%2F3)%5E2%3D30
>>711953362
didn't i just write the same thing?
>>711953358
The confused guy here (me) isn't even OP... I'm just relearning math
28.284271247461900976033774484194
>>711953494
oh thanks, that sounds really graceful like a true mathematician
>>711952834
u can use the angles if want get it easily
>>711953494
9 root 10, you forgot to square the 30
Pythagorean theorem bitch
>>711953494
You used x^2+(x/3)^2=30
You should have used x^2+(x/3)^2=30^2
>>711953705
shit you're right
https://www.cymath.com/answer.php?q=x%5E2%2B(x%2F3)%5E2%3D30%5E2
>>711950021
cos(30)*30=x
x=26
>>711953705
hihi. i knew something was wrong. it just sounded to neat and the value was not enough
AB=x, AE = AB/3, therefore AE=x/3
Using Pythagorean theorem
(x/3)^2+x^2=30^2
(x^2/9)+x^2=30^2
(x^2)[(1/9)+1]=30^2
x^2=(30^2)/(10/9)
x=[(30^2)/(10/9)]^1/2
x=28.46
Women's studies major.
>>711953542
Yes, you did
>>711953891
lol angle isn't 30 degrees mang
This was probably OP's math hw and you faggots just did it for him.
>>711954078
when i was in school we were taught to 'use our resources'. i looked shit up online all the time and argued that was what i was doing. worked
>>711954078
lol
>>711950021
Just take the triangle DEF, since DF and EF have the same length, all the angles have to be the same (60°). So now we know the angle CDF (30°) and solve it by simply using pythagoras.
x=25,98
ok op just bookmark cymath.com and never post a thread like this again lol
>>711954244
so another question to you op:
what's the angle between BE and EF?
>>711953139
this is what I got.
>>711953836
The whole term x/3 is squared, not just the x part.
Apply yourself.
>>711952465
3AE=AB you mong
post another problem faggot
>>711954352
lol nope, try again
>>711954408
workin on it, one sec
>>711954993
i already did it for him. angle between BE and EF. do you know it?
>>711954005
if b is the angle between B and E coming from F,
b+b+c=180
with c being the angle between 30 and 30
in the corners we have
b+a=90
cut a line in between angle c and you get
c/2=a
solve system to get b=60 and c=60
you can figure out the rest.
>>711955208
wait that doesn't prove shit
>>711955208
nope, it's something between 31 and 39 degrees. take sin or something similar
you cant apply pythagoras because we only have one side, therefore theres an insufficient amount of information to work out x.
>>711950021
x*2 + 1/3 * x^2 = 30^2
4/3 * x^2 = 900
x^2 = 675
x = sqrt(675) = 25.98
>>711955121
already close?
>>711950021
3*sqrt(3)
AD and BC are parallel, and, if you take the angle of DF makes with DC, take the secant of it, and multiply by x, you get 30, but secant is one to one on [0,pi/2], and secant is an even function, so we can infer that triangle DCF is congruent to triangle ABE, and triangle BEF is congruent to triangle EFD. Not only that, but the right triangles produced by cutting the isosceles triangles in half produces 4 right triangles that are congruent to ABE and DCF. This shows that FC must be 1/3 of x, so x^2/9 + 9x^2/9 = 30, so x^2 = 27, x = sqrt(27) = 3sqrt(3).
>>711955516
you can find the other one if you try
it is sovleable use some theums niggguh https://www.youtube.com/watch?v=rs66DAJVQQY
>>711955550
should i tell you?
>>711956090
go for it, don't have a calc on me and cant remember the sin cos tan tables lol. it's been far too long since school
>>711950021
fun problem.
split the sides up showing that one side of each right triangle is x/3
i.e. CF = 2 times the length of BF
then pythogrram that shit and it comes out to
x^2 = 810
which is like x = 9root10 or something ugly.
Way to start a thread OP.
ur still a fag tho
>>711955520
30^2 - x^2 = 900 - 675 = 225 = 15^2
FC and AE must be 15, because squares have right angles. But BF and ED must be sqrt(675) - 15 = 10.98. 15>10.98, but x*sec(a) is not equal to x*sec(b), where a and b are two different, non-negative angles on [0,pi/2], so 30 must not be equal to 30. If a and b are two different angles with different signs, like the picture suggests, then BF is larger than FC, so 10.98 is larger than 15.
>>711956090
you already have some information from your question/answer before. take the divided triangle. one side is 30 the other one sqrt(810), the short one one third of sqrt(810).
after that
2 * sin^(-1)[1/3 * sqrt(810) / 30] = 36.87°
>>711955449
Yup, it's sqrt(810)
smallest angle is about 18 and the angle between the 30s is about 36
>>711956558
i'm not op btw lol, i'm an old man who likes math problems
do your own math homework faggot
This is one cheeky ass question, and y'all got baited.
Triangle DEF is an angular bisector, all corners are 60°. By using the law of Sine, sin(alpha) /a = sin(beta)/b =sin(gamma)/c. We can deduct that DE is 30.
The question stated that it gave a square, meaning AD=DC=x.
AD is made up of DE + EA. So x>30.
This will deem impossible when we refer to the Pythagoras. For DF has to be longer than AD.
The question is therefore incorrect.
30
>>711956819
i know. being old is a relative term but probably older than op. i also like math problems. so what the heck. but i think op is not there anymore
>>711951087
Nailed it
>>711952834
Each side of the square (length x) is made of the base of a right triangle with hypothenuse of length 30. And the base of an isosceles with equal sides of length 30. Which is 2 times the length of the base of a right triangle with hypothenuse 30.
So the right triangles have a side that is 30 (it's given with the problem). A side of length x. And a side of length 1/3 x (because each x length side is divided in 3 equal parts).
Solve using pythagoras.
>>711957031
totally wrong but sounds nice
>>711957270
Want me to write it fucking down boy? I'll even draw it for you
>>711957363
read the answers at top of the threat. it's all there already. you're to late bro
Here one for you, baby birds.
Each face of a cube consists of four quarter circles that touch a center circle, all circles and quarter circles have a radius of r. Find the length between A and B in terms of r.
>>711950021
y'all autist faggets
the key is 3*AE=AB=x
Thus :
30² = (x/3)²+x²
900 = x²/9 + x²
900 = 10x²/9
810 = x²
x = sqrt(810) = 9sqrt(10)
>u welcome i'm an engineer
>>711957809
we already had the answer at the top mister engineer. solve the next one.
>>711957535
srqt(24)*r
>>711958211
i like that one
Owh look at muh physics degree, owh İma a fucking engineer. WHY NOT DISPROVE MY LITTLE CLITTY ASSHOLE THEN?
SINE>PYTHAGORAS
>>711958370
mesure it with a ruler b is not the same lenth like the 30 one. oh man. where did you get your degree? at trolling? thumbs up!!!
>>711958370
but nice hand writing though
>>711958673
>measure it with a ruler
What are you fucking 6?
NOBODY measures these shits, that's the golden rule. Why? Nobody fucking knows. I used my rules, guess what. One sides is 2 cm longer. So the shit wouldn't make sense with a ruler either, you fucking dimwit cumstain
>>711958211
This fag is correct
>>711957535
let x be the side of a face :
x²+x² = (4r)²
2x²=16r²
x² = 8r²
Then...
AB² = (4r)² + 8r²
AB² = 24r²
AB = sqrt(24) * r
>>711958370
>>711959009
Confused guy from earlier. This escalated quickly whilst showering...
>>711959009
but you take the task from a totally wrong perspective. you can't assume the the two angles are 60 degrees.
the idea is that you have a square and the lines in between with the length of 30.
after that read what is written at the top of the thread and learn
19.5
>>711959250
don't worry. just trolling.
>>711959243
thanks. you have such cute way to say fag.
>>711959318
Oh boy my almonds are getting on a whole new level of activation. Niggah, do you even Angular Bisector? That's how we find that Shit is 60. And you go about assuming that x/3? That's hypocrisy. I am backed up by scholars. What do you have? Neets from b?
>>711959750
let me be your scholar, pleasssssse
>>711958370
not sure if troll but why the fuck are assuming angles equal 60? that's wrong
i slept through geometry tho
>>711959884
ANGULAR FUCKING BIPOLAR.
>>711951157
You're dumb as fuck OP
>>711959884
it's 60 when the sides have all the same length. so his assumption is wrong because in his drawing he can't prove that b has the length of 30
where is op?
>>711959875
Sure thing mate
>>711959884
sure thing he is trolling. haha.
>>711950021
[(3+1)y]^2 = 30
(4y)^2 = 30
16y^2 = 30
y^2 = 30/16
y = (1/4)sqrt(30)
x = 3y
Thus x = (3/4)sqrt(30)
I'm not trolling, just because Europe is sleeping doesn't mean I am sleeping. I will stay awake to destroy your country and reunite the states for a bigger newer communist one.
>>711960739
still far from truth. but keep destroying
>>711960739
which country? wtf are you talking about?
>>711950021
If this problem were solvable, then why do so many people post different answers?
>>711961230
... This is /b
>>711961230
the one first given were already right. here is someone pretending to be communist. just go a sleep and close the thread
>>711961328
go for it
>>711961230
It's not solvable, I'll tell you a story about a boy named OP.
>be OP
>get bullied by sandniggers and niggers for being a beta
>start a thread to shake things up
>communist guy comes with angular bisector and disproves question and starts Revolutionary
>>711950021
30^2=x^2+(x/3)^2 => 90^2=10*x^2 => x=9*sqrt10
OP here, and wow, a lot of you have autism. This is a middle school math problem at best and 99% of you failed miserably. Kill yourselves.
Correct answer is 9*sqrt(10)
>>711961596
this and no other
op is fun
>>711961640
Better have autism than be a beta nigger faggot who creates 'How can white men even compete' threads.
>>711961975
who's white? which country?
>>711961975
what does communism have to do with it???
>>711961975
who is bipolar again?
>>711962243
Stalin would've capped these faggots like chicken in the orphanage
FC = (1/3)DC
FC = (1/3)x
30 = sqrt[(x^2)+(x^2)/9]
30 = (x/3)sqrt[10]
90/sqrt[10] = x
x = 28.4605
>>711962334
Did you just assume my fucking gender? You degenerate piece of shit
Non-autist here, with an actual answer.
It's solvable with trigonometry and algebra, but I wouldn't necessarily call this a "simple" problem, since the answer is not obviously attainable.
The whole problem hinges on the shape being square. (AE and CF are of equal length.)
System of equations:
3(30sinθ)=X
30cosθ=X
3(30sinθ)=30cosθ
3sinθ=cosθ
3=(cosθ)/(sinθ)
3=cot(θ)
θ=arccot(3)
Substitute:
30cosθ=X
30cos(arccot(3))=X
Final answer:
X=28.4604989415
>>711960703
I kinda fucked up here for some reason, but I'm on the right track (I actually have a degree in math, but I guess my retard came out there for a sec)
We know that the top (the little triangle) is a right triangle, therefore by the Pythagorean theorem, we have a^2 + b^2 = c^2.
c represents the hypotenuse (BE), which in this case is 30 units. So c^2 = 30^2 = 900
What about the other two sides though? Lets represent the shortest side (AE) by y.
Now, side AB is equal to side AD. And side AD is equal to AE + ED. However ED is twice as long as AE. Thus AD is equal to AE + 2AE = 3AE. But then since AD = AB, we also know that AB = 3 AE.
Next since AE = y we now know that AB = 3 AE.
Now we just need to plug these values into the Pythagorean theorem.
We have:
(AE)^2 + (AB)^2 = (BE)^2
i.e.
y^2 + (3y)^2 = 30^2
y^2 + 9y^2 = 900
10y^2 = 900
y^2 = 90
y = sqrt(90) = (3)sqrt(10)
Finally, since AB = 3y and y = (3)sqrt(10), we have:
AB = 3y = (3)[(3)sqrt(10)] = (9)sqrt(10)
which is roughly 28.46 units
>>711962549
It should be solvable using just Euclidean geometry. Your solution works, but its less elegant and precise.
>>711962961
looks pretty elegant to me. i like both approaches.
>>711960739
Yes, you see that would all be very well, but those proportion don't work. Two 30/60/90 triangles together form an elongated rectangle, not a square.
>>711950021
wew didn't think i'd get this one right
>>711963197
It's inelegant just in the sense that it requires more background assumptions (namely of the definitions and theorems of trigonometry). However, I do rather like this solution as well.
>>711950021
i like the symmetry
30 = 10√9
x = 9√10
fc = √9√10
>>711963890
i see
>>711950021
More like, being able to solve this problem means you have autism...
>>711964272
of course op. go to bed
>>711963908
Autist
>>711964272
>is brainlet
>can't solve the problem or interpret any of the posts in which the solution has already been posted
>feels self conscious about it
>decides to insult people that can
>Will never have a career in STEM, medicine, finance, accounting or any other lucrative and intellectually engaging job
Ok here's one.
This cube has a hollow cube inside of it. Line AB fits perfectly vertically. Line BC = 10.
Find the volume on the shape.
28.5
>>711950021
E1: y^2 = 30^2 - x^2
E2: 3*y = x
9*x^2 = 900 - x^2
8x^2 = 900
x^2 = 900/8
x = sqrt(900/8)
or yknow,
x = 15/sqrt(2)
>>711950021
>OP having trouble with his underage math but is too embarrassed to ask parents or teacher for help.
Stop trying to bait us into doing your homework anon. That's not how you learn.
>>711965873
is it 2000*sqrt(2) - 125? did in my head
