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Solve.
>>
no
>>
15
>>
15
>>
ez 25
>>
15
>>
52
>>
>>711819666
Since you can't assume a relation between the image with a single beer mug and any other image in the post this question does not have a solution.

/thread
>>
25
>>
>>711819666
25
>>
16
>>
>>711819666
17
>>
1 bottle = 10
1 burger = 5
2 pints = 2
1 pint = 1

burger + pint x bottle
5 + 1 x 10 = 60
>>
>>711819666
60
>>
>>711819666
15, stupid question
>>
>>711819666
17 you fucking retards.

Bottle = 10
Burger = 5
Mug = 2

FUCK you faggots are dumb.
>>
>>711819755
This guy got it and still got dubs
>>
i got 16

Bottle = 10
Burger = 5
Mug = 1
>>
16
>>
>>711819935
bro do you even pemdas?
>>
>>711819935
Youre dumb multiplication is done before you add
>>
>>711819988
2 mugs is half of one mug tho. thats the whole point.
>>
>>711819666
15 you retarded faggots
>>
>>711819666
60. Also, fucking chek'd satanic trips.
>>
>>711819666
>1 beer = 10
>1 burger = 5
>1 jugs = 1
1 burger (10) + 1 jug (1) x 1 beer (5) = 15

>Answer is 15
>>
>>711819835
interesting
>>
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1 burger + 1 pint x bottle

5 + 1 x 10
>>
>>711820050
Your*
>>
If you wanna be real serious about it, the image of two pints=2, but we don't know what the image of one pint is, thus we don't know the answer.
>>
>>711819666
25
>>
>>711820129
what I find interesting is anons who asume the image with one beer MUST be worth half of what the image with two beers is worth.

based on absolutely nothing in this problem.
>>
remember children, use the basic method of working equations that you were taught many years ago!

BIDMAS:
Brackets
Indices
Division
Multiplication
Addition
Subtraction
>>
>>711819835
Doesn't seem hard to assume two mugs is 2X one mug...
>>
As if it wasn't obvious already:
15
>>
>>711819666
10 + 10 + 10 = 30
10 + 5 + 5 = 20
5 + 2 + 2 = 9

5 +1 x 10 =
5 + (1 x 10) =
5 + 10 = 15

Order Of Operations - basic Elementary School-level math
>>
>>711820160
Yes we do. 1 pint is 1
>>
15
everything else is bs
>>
>>711819666
25 way too ez
>>
>>711820239
Why would you assume that one mug equals two mugs?
>>
25 you autistic shitz
>>
>>711819894
This
>>
PEMDAS
Parenthesis
Exponents
Multiplication / Division
Addition / Subtraction
>>
>>711820106
>1 beer = 10
>1 beer (5)
>>
15
>>
>>711820482
I didnt realise that the last thing was X
>>
>>711820300
This guys right
>>
>>711819666
60, fuck off with your gay thread
>>
>>711820270
based on what? on the image itself?
that is ridiculous.

the link between the image with two beers and the image with one beer is only in your mind. In math they are two completely different variables.

but but 2 should cost twice as much as 1 no?
maybe it is buy one get one 50% off at o'malleys pub today, did you think of that?
>>
>>711819835
True, but assuming it means 1 the answer is 15
>>
25
>>
>>711819666
1 BEER = 10
1 hamburger = 5
1 mug = 2
5 + 2 x 10 = 25
>>
>>711820872
No 2 mugs equals 2 one mug should be 1
>>
>>711820790
wrong again, now you are assuming the question is in base 10.
>>
>>711819666
a + a + a = 30
3a = 30
a = 30/3
a = 10

a + b + b = 20
10 + b + b = 20
b + b = 20-10
2b=10
b = 10/2
b = 5

b + c + c = 9
5 + c + c = 9
c + c = 9-5
2c = 4
c = 4/2
c = 2

b + c + a = d
5 + 2 + 10 = d
d = 17
>>
>>711820949
dafuq? why should the image of one mug be worth half of the image of two mugs?

the relation is only in your mind
>>
>>711820762
But even then what you said only applies to the second mug so what you said is completely irrelevant
>>
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>>711820973
>>
Check my math /b/

came up with 25
>>
>>711821015
Ooops, misread that last equation; it's actually b+c*a = d
b + (c*a) = d
5 + (2*10) = d
5 + 20 = d
d = 25
>>
>>711819666
This was trickier than I first thought.
>>
>>711821047
It is not irrelevant.

if this was a math problem there would be a variable (x) for the image with two mugs and a completely different variable (y) for a single mug. No relation is given in this problem between x and y, thinking that y is worth half of x is only in your mind.


Try solving that.
>>
10+10+10=30
10+5+5=20
5+2+2=9
5+2*10=25
>>
>>711821015
But in the last equation it's a single mug, not two. Your last equation shouldn't have "c" in it at all.
>>
>>711820270
The partial outline of the mug that's behind the other one could potentially have a completely different value, as it's not proven to be identical to the one in front.
>>
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Bottle: a; Burger: b; Beer: c

(1) a+a+a=30 |:3
-> a=10

(2) a+b+b=20
-> 10+2b=20 |-10
-> 2b=10 |:2
-> b=5

(3) b+c+c=9
-> 5+2c=9 |-5
-> 2c=4 |:2
->c=2

(4) b+(c*a)=x
-> x=5+(2*10)
-> x=5+20
-> x=25
>>
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>>711820057
>>>711819988
>2 mugs is half of one mug tho. thats the whole point.
>2 mugs is half of one mug tho
>2 mugs is half of one
>2 is half of one
You dense mother fucker.
>>
>>711821267
blind
>>
>>711821177
Y is worth half of x because in x theres two images of pints and in y there is only one. Basic maths and unless we get told other wise by how the problem is set out y is worth half of x
>>
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>>711819835
this guy has it.
>>
>>711819666
lmao grade 9 algebra
>>
>>711821222
Oh goddamn, you're right.

That would make 15, assuming that single mug is 1/2 of double mug.
>>
>>711819666

15
>>
>>711821367
who told you an image with one pint is worth half of what an image with two pints is worth?

I am seriously concerned with people who assume this with absolutely no basis specified in the problem
>>
>>711819988
Bro its multiplied by 10 not add 10 lol
>>
Bottle + Bottle + Bottle is 30, so Bottle = 10
Bottle + Hamburger + Hamburger = 20, so Hamburger = 5
Hamburger + (2)Mug + (2)Mug = 9, so (2)Mug = 2 and Mug = 1
Hamburger + Mug × Bottle
Hamburger + 10
5 + 10
15
This is the only answer, because why else would you intentionally include a different image of a single mug in the question.
Either that or a single mug is an undefined variable and we can't solve it
>>
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>>711821367
>>
This problem doesn't make sense, how would you multiply a draft beer by a bottle beer?
>>
>>711819666
10+10+10=30
10+5+5=20
5+2+2=9
10(2+5)=70

not that hard
>>
>>711820136
You're* dumb bitches
>>
Always the same shit... Get a life OP...
>>
>>711819666
Satan can't math. This is the proof
>>
there is no symbol between the mugs, so they must be multiplied together.
>>
>>711820270
typical peasant
>>
>>711819666
Simple bottle is 10
Humburger is 4
And there is no 9 in octal.
>>
>>711821488
>assuming that single mug is 1/2 of double mug

and assuming a single mug costs just as much as two mugs because it is buy one get one free at the pub today?

I mean since we are making idiotic assumptions and all
>>
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>>711821579
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>>711821579
Fuck what was i thinking
>>
>>711819666
A bloated stomach
>>
17
>>
>>711821523
Its a part of the education system? Well in australia thats how we got taught to do.these type of problems. No wonder we all get portrayed as fucking retards
>>
>>711819666
70. Beer is worth 10, burger is 5, and a mug is 2. But like the other Anon said, we don't see a problem where we can test the number we assume for the mug against the beer.
>>
>>711820270
2x1=11?
2xo=8?

The symbols have no connection unless one is described
>>
>>711821807
70*
didnt notice the x
>>
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>>711819666
checked
answer is 60
>>
>>711819666
? = lunch.
>>
>>711819666
b h g n

3 0 0 30
1 2 0 20
0 1 4 9

h + (g x b) = x

3 0 0 30 > 1 0 0 10
1 2 0 20
0 1 4 9

1 0 0 10 -1 0 0 -10
1 2 0 20 > +(-1 0 0 -10)
0 1 4 9

1 0 0 10
0 2 0 10 > 0 1 0 5
0 1 4 9

1 0 0 10
0 1 0 5 0 -1 0 -5
0 1 4 9 > +(0 -1 0 -5)

1 0 0 10
0 1 0 5
0 0 4 4 > 0 0 1 1

1 0 0 10
0 1 0 5
0 0 1 1

h + (g x b) = x

>5 + (1 x 10) = 15
>>
>>711821643
this man is correct.
Bottle =10
Burger = 5
Mug = √2

? = 5 + 10√2
>>
60
>>
>>711821809
maybe, a computer would never make that mistake.

who is better? you decide
>>
>>711820300
this guy + check 'em dubs
>>
>>711821910
60*
didnt notice that there were only 1 mug
>>
It's a fine night whit a beer, a burger and a little bit of anal penetration with a bottle that's what it is
>>
a nice evening, now fuck off
>>
17
>>
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>>711819666
Sixteen
>>
OOOH its 25 guys.
>>
>>711819666
Set one work out beer:
30/3 = 10
Beer = 10

Set two work out burger:
We know beer = 10 so take it away
20-10 = 10
10/2 = 5
burger = 5

Set three work out pint:
So burger = 5 take it away
9-5 = 4
4/2 = 2
pint = 2

Set four work out last step:
So the a trick it's only 1 pint since the image only shows 1 instead of 2.
Beer = 10
burger = 5
pint = 1

5+1*10 = 60

The answer is 60
>>
>>711819666
10+10+10=30
10+5+5=20
5+2+2=9

Depending on interpretation...
5+(2/2)x10 = 15
or
5 + undefined variable x undefined variable = NaN
or
5 + undefined variable x undefined variable = 5
>>
>>711819666
The answer is in my post number faggots
>>
>>711819666
Fuck op went and did a winrar and got trips for satan nigga
>>
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/thread
>>
>>711822716
Set one work out beer:
30/3 = 10
Beer = 10

Set two work out burger:
We know beer = 10 so take it away
20-10 = 10
10/2 = 5
burger = 5

Set three work out pint:
So burger = 5 take it away
9-5 = 4
4/2 = 2
pint = 2

Set four work out last step:
So the a trick it's only 1 pint since the image only shows 1 instead of 2.
Beer = 10
burger = 5
pint = 1

5+1*10 = x

Forgot BIDMAS

1*10=10
10+5=15

Answer is 15
>>
25
>>
All the arts majors trying to get fancy with their interpretations of the philosophical manifestations of 1 vs 2 beer mugs need to fuck off.

How retarded can you be?

Mathematics is a language that represents real life situations. If they do not state otherwise we go with convention. Convention is that 2 mugs is equal to 2*1 mug.

Fucking B.A need to get a job.

Also 15.

3 equations 3 unknowns. Theres no need to solve this to know theres only 1 solution.
>>
>>711823664
>Convention is that 2 mugs is equal to 2*1 mug.

holly shit, can I have whatever you are smoking?
>>
>>711821977
only response i've seen that's worth posting
>>
>>711819666
Hail Satan

Also, Saturday brunch
>>
>>711823664
actually, convention would be that 2 mugs is mug times mug
>>
>>711819835
B+B+B=30
3B=30
B=10

B+V+V=20
10+2V=20
2V=10
V=5

V+W+W=9
5+2W=9
2W=4
W=2

B+V+W= ?
10+5+2= 17

I would know i'm a physicist
>>
>>711823789
Go back to women studies.

Math isnt for the retarded.

I have 1 ball. Multiply by 2. I have 2 balls.
>>
>>711824133
I meant
B+VxW= ?
10+5x2= 20
>>
>>711824079
Lol moron.

Mug*mug = mug^2

So a weird hyperdimensional mug.

2 mugs = 2 * 1 mug

How bad were you kids at math.
>>
>>711824133
>B+V+W= ?
>10+5+2= 17
>I would know i'm a physicist


burger + draft x bottle
all those years of school wasted
>>
Answer: A stomach ache.
>>
>>711821523

I'm with ya. How do you know they are the same beer? Maybe they're different alcohol percentages. maybe one is piss.

For the point of the argument, I'm sure the problem wants you to assume the single beer is half of the double beer picture, but anon is right, you shouldn't just assume this without context. if this was in a 5th grade math book i'd say sure, go ahead and assume. if this was in an far far more advanced class or a philosophy class, we might want to look more into it.

just my thoughts.
>>
>5+1*10
>somehow people will get 60 as the result
What the fuck guys, how do you fuck up this hard
>>
>>711819666
17.
>>
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>>711819666
3 beer = 30 -> beer = 10
beer + 2*burger = 10 + 2* burger = 20 -> burger = 5
burger + 2*mug = 5 + 2*mug = 9 -> mug = 2
burger + mug + beer = 5+ 2*10 = 25

glad my math degree is getting some use
>>
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check em faggot. my satanic trips say the answer is fuck urself
>>
>>711824528
Missed the multiplication -- the answer is 100.
>>
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>>
22 you retards
>>
>>711824463
no dumbass, in math you are supposed to assume normality unless otherwise stated.

If we continue with your logic, how do you know that we arent counting the molecules inside the glass blown to make the bottles. Those can be different.

It never ends if you keep asking these kinds of stupid questions.

If I say: "what is 1+1"

You should assume normal convention and say 2.

However, if I was to add in base two then the answer would be: 10

It is on the individual posing the question to make all complications known. The person answering must then use the simplest conventions to interpret the question.
>>
25, idiots..
>>
>>711824155
you have a funny way of looking at life.

there are no balls, you have an image that happens to depict two beers and a completely different image that happens to depict one beer.

any association between these two images is only in your mind
>>
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You should be able to solve this
>>
>>711824133
>>711824238
you fucked it up again m8; V + B*W since you made V = burger
>>
>>711824839
tan needs to be stated with an argument.
>>
>>711825103
It's arctan you fucking pleb, the argument is after the -1
>>
>>711819666
30÷3=10
Beer = 10
10+5+5=20
Burger = 5
5+2+2=9
Beer mug = 2
5+2×10= 70
This is some 7th grade algebra here also satan trips checked
>>
>>711825103
different anon but first of all it's arctan, second there an anoying habit in math to exclude parenthesis like douche nozzles, the exponential beer however make no fucking sense..
integral [ arctan(burger/cage)/(cage*ln(mug))^beer) dcage
>>
>>711825199
>>711825323

assuming just the ln is to the power of beer

cage = x

19.5313x^2arctan(5/x) + 97.6563x - 488.281arctan(0.2x) + C
>>
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Clearly you are all fucking inbred nigger tards, the answer is 67. PEMDAS anyone?
>>
OP is a faggot, this puzzle has no challenge.

I'll show you how to make a brain challenge.

Can you find a seven digit number which describes itself.

The first digit is the number of zeros in the number.
The second digit is the number of ones in the number, etc.

For example, in the number 21200, there are 2 zeros, 1 one, 2 twos, 0 threes and 0 fours.

C'mon, probe you are not a fucking faggot
>>
10000000 SHEKELLIONS YOU FUCKING FAGGOTS
>>
>>711821311
this lmao
>>
>>711819666
16
>>
>>711819666
15
5+(1x10)
>>
>>711826666

Better challenge and quads of truth
>>
>>711819935
>pints
dude those are 500mL containers of beer, not pints of beer.
>>
>>711826666
nice devils trips embedded in those quads

but too easy

3211000
>>
>>711819666
It is 70
>>
>>711819666
It is 60 you faggots
>>
>>711828050
Wrong
>>
>>711829005
You must be a mongoloid.

Its correct.

3211000

Has 3 zeros
has 2 ones
has 1 two
has 1 three
has 0 fours
has 0 fives
has 0 sixes
>>
>>711829005
Nop, its correct

Also 6000000
>>
19.5
>>
>>711829112
That won't work because there's a six in your number. Therefore you should have a 1 at the seventh position. But then you would need a 1 at the oneth position. and so on. Then it derails.
>>
70
>>
>>711821120
You write your x's like a faggot.
>>
>>711819666

74
>>
>>711819666
15
Order of operations
>>
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>>711819988
Thread replies: 163
Thread images: 20


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