You should be able to solve this.
The stories and information posted here are artistic works of fiction and falsehood.
Only a fool would take anything posted here as fact.
Only a fool would take anything posted here as fact.
You should be able to solve this.
>>688548750
Are we talking turn based combat?
Everyone gets one shot in that order, then they start again?
Without any calcuation I would say White should first try to kill Black.
Anyway I see a really low chance of survival.
>>688548750
Someone solve please
>>688548750
Given the insufficient information you have provided, the answer is probably to not draw his weapon. That way, Mr. Gray will fire at Mr. Black, knowing that he is due to fire next and will definitely hit.
If Black survives, then he will hopefully fire back at Grey. That will leave White as the only one left to fire, and since the standoff will definitely end in 2 deaths, he now essentially has a 100% chance to hit because of that rule.
>>688548750
white should miss on purpose
Is this middleschool?
>>688550510
Correct if he shot first and hit anyone it would make is situation worse.
>>688550510
white has a 25% chance to hit target.
if target is air, then he has a 75% change to hit grey or black.
>>688548750
>Mr. White shoots Mr. Gray first
>Incapacitates Mr. Gray
>Mr. Gray is bleeding out from the shoulder on the ground, but still alive
>Mr. White begins running as quickly as he can around both Mr. Gray and Mr. Black
>Mr. Black will eliminate his easiest target, the one who is still
>Takes his time shooting Mr. Gray and finishes him
>Mr. White now slows down with the advantage of time he has over Mr. Black
>Shoots Mr. Black
>>688550508
This is correct. Think of it like a turn-order.
White delays his turn. That means that Gray MUST shoot at Black, because if Gray shoots at White and hits, then Black can only shoot Gray and will definitely hit. This results in Gray having a 75% chance to eliminate Black.
If he hits, white wins, if he misses, white still has a 50% chance of survival assuming the Black selects his target randomly.
>>688548750
Mr. White just needs to wait for the cops to send Mr. Black to prison and since Mr. Gray has a little black in him he'll be sent to county jail and this isn't a run on sentence at all because it's really concise and why are you still reading as you should really give me the next problem to solve.
>>688551716
of course not, families create less children and therefore less women.
>>688548750
White should shoot himself in the arm.
>>688546392
>>688551554
lol
>>688552249
touché
>>688551716
nah it didnt because when parents have a son first they can never have a girl to balance it out
u will c from the following maths that i am correct
if boy 50% chance = 100% boy
if girl 50% chance = 25% boy
this is because after the first girl there can either be a boy making the ratio of boys 50%, or another girl but thats only 25% chance of total
so like
50% chance that 100% boys
25% chance that 50% boys
12.5% chance that 25% boys
and such there will be 66.6% guys and 33.3% girls
>>688551716
You're flipping a coin. If it lands heads, stop flipping, if it lands tails, flip again.
Are you more likely to get a greater number of heads, or tails?
Not sure how to work this one out. I could write a program quickly to flip a coin 10,000 times and check the results, but I'm going to bed soon so I can't be bothered.
>>688553576
>>688552748
so wrong buddy
>>688553576
>>688553823 stay in the box bitch
>>688553576
>>688548750
White should shoot himself in the foot, making himself a useless target. The game ends if Gray hits Black or Black hits Gray, and White survives regardless.
>>688554024
splain
>>688552249
Retard
>>688551716
Assuming that families produce children until a boy, the numbers will stay the same.
First round (no one has any kids) - Half will be boys, half will be girls. It's 50/50 now. The families with boys stop having kids. the other ones continue.
Round 2 - 50% will be boys, 50% will be girls. Hmm, the split is still 50/50. The boy families stop, the girl families continue.
Round 3 - 50% boys, 50% girls. I'm starting to see a pattern here.
Each round will produce the same number of boys and girls. The next round will have only half the participants of the previous round, and the ratio will remain.
>>688548750
>Expecting Black to play by the rules.
Ya see, that's the problem.
>>688552766
But this isn't as simple as flipping a coin.
Assume we 50 males (M0) and 50 females (F0).
They couple off and copulate.
Let's assume the result is 10 males (M1) and 15 females (F1).
For simplicity, we then assume that the 15 original couples then have males.
So to recap, before it gets convoluted, we have: 50 M0
50 F0
25 M1
15 F0
We can now say that M0 and F0 can copulate with a DIFFERENT person to create a new couple. This continues until no novel couples in these two categories can copulate.
We can also say that M1 can keep copulating with F1 until no new novel couples can be made.
We can also say that M0 can copulate with F1 (provided that that it's not with their children). This also applies to F0 and and M1.
As you can see this problem gets out of hand really fast. Of course you can set restrictions to make it simpler.
>>688555248
This one's impossible unless we accept that electricity doesn't have to originate from the source and that the houses can connect to one another for power.
>>688554177
Nope. Bonus points to >>688553823 for thinking outside the box, nobody said the box was a constraint. That solution is simpler than yours
>>688546392
I did it
>>688555827
you are a genius
>>688551716
That's your average geometric distribution:
(1-p)^(n-1) * p, where p=0,5 the probability of a boy
The expected value of the geom. dist. is 1/p => 1/0.5=2
This means the waiting time till you get a boy is 2, or every second child is a boy.
So you end with a 50-50 ratio.
>>688546392
fugg
>>688556037
312211
>>688555248
This >>688555727
Stop trolling
>>688555738
CROSS NO LINES. THE BOX IS LINES.
>>688556037
That a really mean one.
I recently had that in combinatorics, so I can confirm this >>688556339
>>688556037
11112211
>>688555248
688556037
3.
>>688556339
Correct
>Three ones two twos one one
>>688556952
dialing
>>688551716
Well, the only explanation I see is that they had a law of one child before and people have been killing newborn daughters. Just like in China.
>>688556037
312211
If you say each line out loud that is how you find the next line.
one
one one
two one
etc
>>688557202
Sorry, just a faggot and forgot the ">>"
>>688556861
nope faggot retard
>>688557470
x = 26.87 units
>>688557470
19. EZ.
>>688556339
13112221
>>688557739
1113213211
>>688557670
this
>>688557739
1113213211
I actually figured this
>>688557470
I'm sure 19 looks like the halfway point... Which means the full length would be 38. Meaning it'd be 53.7
>>688557944
31131211131221
>>688557670
Wrong learn to math.
>>688557470
A^2+B^2=C^2
>>688556735
Autism
>>688558100
13211311123113112211
>>688558061
Lmao what. The line means each line is congruent
>>688557470
According to the line, all 3 of the lines are congruent. That means it is 19
>>688558708
11131221133112132113212221
>>688556735
"Use three lines [...] without crossing the lines"
That fucking definite article there serves a purpose, you dumb shit. If it was "without crossing lines" then you could argue that the box lines couldn't be crossed, but when you say "without crossing THE lines" it's reffering only to the three lines mentioned before.
>>688556037
I feel like a retard not getting it. Someone explain
>>688558936
50% the previous tosses are already defined so the don't count for the odds
>>688555248
Not crossing any line, just crossing the whole company
>>688558936
0.5, since the first 4 results are guaranteed.
>>688558936
50%
>>688558644
What this faggot said.
so it would be: 26.87
>>688555248
mathematically not possible
>>688558846
The fuck are you talking about, there is a right angle, therefore the opposite side is the hypotenuse and pythagoras gives 26,8
>>688559071
In the first row there is:
1
Second row:
There is one 1 = 11
Third row:
There is now two ones = 21
etc
>>688559071
You have to speak it out loud:
You start with a 1.
So you have one 1 =>11
Now you have two 1 =>21
Now you have one 2 and one 1 =>1211
Now you have one 1 and one 2 and two 1 => 111221
...
>>688556218
winrar
>>688559475
That is what you would think with your soft human brain but the answer is 19.
>>688558186
>look mom im trying to troll
>>688553576
Try and solve it without looking up the answer.
>>688558846
>>688559475
nobody said it was enclidean geometry though. You can have both right angles and three equal sides e.g. if you draw this in a circle's surface.
This is the most sensible assumption, or else the notation is wrong and the puzzle is pointless
>>688559923
Pretty sure a triangle with 3 equal sides has three angles of 60°. That's not what the drawing looks like.
If I missed something, enlighten me.
>>688559475
>>688560199
* Sphere, I meant sphere. Apparently your brain condition is contagious
>>688548750
He should try to shoot himself in the foot. If he succeeds, he is one of the two shot, and grey will have to shoot black to try to save himself, otherwise black will have to shoot him to make a 2nd victim.
>>688560461
Do you see "drawn to scale" written on that whiteboard?
>>688560461
anon quit arguing with retards
>>688560151
answer is 2
number of circles/ovals in the cipher
8 = 2
6 = 1
9 = 1
0 = 1
>>688557470
26,870057685088805927232085759984...
>>688559297
I like this solution. Gas plant also needs some water, doesn't it?
>>688560723
That one got me. Thanks.
>>688561173
Do you even know what the small square in the corner means?
>>688548750
Gray knows he wont survive, shoots himself just while saying fuck you to white
>>688561525
Who are you replying to?
>>688561407
switch, before the chance was 1/4 to hit the price, now it's 1/3
>>688555727
The way is through
>>688561407
change
odds of first decision is 1/4
odds of second decision is 1/3
>>688561407
Always switch
>>688561173
How can you be sure that all 3 side lengths are equal without anything saying so specifically? The only thing specified is that its 90 degrees. Did you fail high school geometry?
>>688558846
This. It's a spherical triangle.
>>688561684
Not him, but it does say that specifically
>>688555248
Trust me, I'm an engineer
>>688561746
Guys i have work to do but solving these is fun. Should i go work or stay?
>>688560151
2 easy ;D
>>688561407
I've read something shit about probabilities, that you should choose another door to get the price... But I still don't understand why.
>>688555248
This one is impossible. Unless the earth is Taurus shaped
>>688561939
What kind of retard are you, go to work faggot
>>688562101
To get it right 2 times in a row with 4 possibilities would be 1/8 chance. By switching, you reset your chances to a 1/3 chance.
>>688561939
Connect work to utilities with only one line
>>688561407
Before door B is opened, the probability of A being right is 25% and the prob. of A being wrong is 75%.
After door B is out of the way, the prob. of door A being right is still 25%, and A being wrong is still 75%.
Therefore C and D share the 75%, or they both have 37,5% of being right, while A still has 25%
So you switch.
>>688562006
Stay if more fags upload more
>>688562339
What does this mean
Harder one.
>>688562513
Not possible or there is a 1/10000 chance
>>688562513
100%
>>688562513
how did you get to check in without boarding pass?
>>688561868
me too
>>688556945
>>688562767
Disregard the second statement as its permutation not combination
>>688562387
It was a joke referencing one of the puzzles in this thread.
Maybe you shouldn't go to work
>>688561939
Do you get money for that work? Go.
You don't? Stay.
>>688556037
i remember my 9th grade algebra teacher showing us this. got frustrated as fuck trying to figure it out and felt like a dumbass when i saw the solution
>>688555248
Trust me, i too am an engineer
>>688562767
>>688562796
Nope and that is some variance between answers.
>>688563839
last person to sit will always be flight attendant performing final checks, or in rare cases pilot
>>688562958
I got the reference but why utilities?
>>688562513
0%. They check your boarding pass on the plane. You did not get on the plane.
>>688555248
This one is only possible if the houses and companies are on a 3d donut shaped planet
>>688562513
99!/100!
1%
>>688564756
1/7
>>688563655
Solved.
>>688564900
ding ding nigga
sloved
>>688551716
King is stupid fuck
>>688562350
not saying your wrong, but this is the part of finite math i never could quite grasp. care to give me a brief explanation of why the probability for A,C and D are not all equal after B is opened? Is B not then a known result, indicating that you should re-evaluate the situation to end in a 1/3 shot for each remaining door?
>>688564756
29.17% is red
>>688565530
you're*
...sorry
>>688564900
Wrong sorry.
>>688548750
>Apologize on behalf of his ancestors for enslaving Mr. Black's ancestors and offer him a high-paying position in his company.
>>688561407
Does it even matter if you switch? If the second door is opened you also reset your chance, so couldnt you just rechoose the one you pickex earlier for 1/3 chance?
>>688564756
7 red:24 blue
>>688555248
Just go through houses 1 & 2 for two lines
>>688564756
>>688565848
top kike
>>688561407
The switching is nonsense in my eyes.
When you first pick a door, you have 25% to win. So after you know, that in the door you didnt choose is nothing, you now have the chance to choose again. So you now look at three doors, which implies every door now has a 33% probability. If you choose A again, you "stay" at the same door, but the chance rose to 33% instead of the previous 25%. If you change or not doesnt matter.
>>688564756
1/4
>>688561623
I don't get it.
Let's turn the problem around : I pick door B, are you still going to show me that door B doesn't have anything behind it, or will you show me another empty door ? If so, I can consider you will always show me an empty door, whichever door I choose first. Therefore there's only 3 doors since the beginning of the problem, 2 empty and 1 with the prize. If we consider things this way, I've always had 1/3 chance to get the prize. Isn't it ? I just don't get why it should raise from 1/4 to 1/3 since you have done nothing but showing me that one of the doors I didn't choose would have led me to nothing. I wasn't part of my choice since the beginning, how could it alter my odds ?
>>688566136
Correct
>>688566060
That's what you'd initially say. Doesn't wok like that.
Google 'monty hall paradox'
>>688566708
50/50
>>688562513
1 / 100^100
>>688566708
66%
>>688565530
Not sure if I can explain this properly, but the point is that the probabilities stay the same.
A has 25% of being right.
When you reveal a door, it stays in the sample. There are still four door and you adopte the previous prob. of being right/wrong.
This probably doesn't help enough but it's been years since I got it explained to.
>>688564756
A plane is infinite so both parts would be an infinite percentage of infinity ‰
>>688566708
2 coins which are Head / Head and Head / Tail
3 Head / 1 Tail
Landing on Head leaves 2 Heads possible and 1 Tail. --> 66% chance that the other face of the coin is Head too.
>>688564756
24:7 = 22,58
>>688561623
>>688561637
>>688562350
Door A is still part of the 1/3 you fucks, no matter what you do you have a 1/3 chance of being right. Door A doesn't have less of a chance because you picked it first.
>>688567256
Retard confirmed
>>688567557
Incorrect. The first door is still 1/4, the other 2 are 1/3.
1/4, X, 1/3, 1/3.
If you're too simple minded to understand this, watch Mythbusters.
>>688567190
The first night 100 Blue ayed people would get out
The second night 100 others people
Guru remains on the island until figure out his eye color.
>>688564756
The smallest coherent and recurring shape is two red triangles and one blue hexagon. Therefore:
n*2/n*6 = 1/3
>>688566187
let's simplify it to three doors
1/3 chance to pick the price, so the odds when not changing are 1/3
however the odds to pick a wrong door are 2/3. and after one wrong door has been opened, the chances that you picked a wrong door are still 2/3, and the chances you picked the price are still 1/3. that means the other door has a 2/3 chance to have the pric and a 1/3 chance to be wrong.
Sorry for the wrong format, can't be bothered to photoshop now.
>>688567190
Do we assume that every single islander is there to listen the guru?
>>688564756
Take a pattern that you can glue to itself to make it expand at infinity, you cannot do that with the one in the picture. For example take a bigger hexagon of 7 blue hexagons + 12 red triangles, whose total area is 7*6 + 12 triangles, you get a ratio of 12:54 red surface.
>>688568210
No.
>>688568397
Yes.
>>688568436
T R U M P
R
R
U
M
P
>>688567444
That wasn't the question.
>>688566136
this
>>688562513
Answer is 50%
Take the first guy sitting down at random.
1 in 100 chance he sits in his own seat. After that everyone including the final passenger would sit in their own seat.
1 in 100 chance he sits in final passenger seat. Now final passenger can never sit in their own seat.
98 in 100 chance he sits in some unrelated guys seat and it goes to the next person.
Each person will give the same 50/50 chance they either sit in their own seat or the final passengers seat.
>>688546392
Who needs 4 you losers?
>>688568436
>>688569078
3 times
>>688567190
>>688568477
Well the question ask "who" like we could identify anyone.. Which is not possible unless it's the Guru.
But the Guru can't know his own eye color because they all can't communicate and therefore no one can tell "i see one green eyed person" so...
I would say that the first year, everyone would try to get out of the island by saying "i have blue eyes" because of the Guru that said "I see at least one blue eyed person".
Other idea is that they know the first pargraph, therefor they know that they are a group of people with assorted eye and so know tha count is 100/100 + the guru
>>688567190
If anyone wants the answer to this one. Because lets be honest none of us are smart enough for it.
https://xkcd.com/solution.html
Warning spoilers in link above.
>>688568944
"middle"
>Loser
>>688569503
Incorrect
>>688569553
Correct
>>688568806
>streight
nigga it's right above where you wrote
>>688555248
>>688569078
two.
Pick any three balls for the left side, any three balls for the right side, and three balls set to the side. If the light ball is on either side of the scale you've narrowed it down to three balls. If the two sides weigh the same, then the light ball is one of the three balls set aside.
Of the remaining three balls, one goes on the left side, one goes on the right, and the last one is set aside. Same logic applies.
>>688569078
1) Weigt two of them.
2) If no difference, weigh two more.
3) Rinse, repeat.
4) Again.
If still in balance, the 9th ball is lighter.
Can you solve it with less steps?
>>688567190
everyone, and on the 201st night
>>688569553
LELE that was easy but the problem miss something:
People can only try tpo quit the island ONCE and then yes it s the answer.. Otherwise, if someone tells me that he see blue eyed people i would try the first night to tell that i have blue eyes even if i see some other people with blue eyes.
But indeed, if trying and being wrong means you stay on the island forever then yeah, you would wait to confirm your theory.. Otherwise you're out on the first night and that's it. Dumb
>>688562350
37,5 or 3/8 chances, correct
>>688569792
Is this a diet question?
>>688567557
I'll stick with this. I understand the other guys' logic, but since B is out there are only 3 possibilities and one of them is yours i.e. 1/3.
>>688548750
Shouldnt do anything
>>688570338
Where is the question... ?
>>688570655
>They find 100 gold coins they must decide how to distribute them.
>>688561623
>you have 4 apples, one is safe, rest are poisoned
>you choose apple 2
>apple 1 gets eliminated
>do you still want to eat apple 2 or do you want to switch to apple 3
each apple before elimination
1/4 1/4 1/4 1/4
Each apple after elimination
1/3 1/3 1/3
Literally nothing changes, your odds are just slightly better, if you change it makes no difference.
>>688548750
Hide behind cover.
>>688551716
Yes. Since the families wanted to have more children, they did as the Chinese do, and killed the wrong gendered child.
>>688553576
pic related ya fucking retards
>>688555248
pic related 2
>>688556037
32
>>688558936
50%, although it depends on how the coin is weighted so it could give or take a percentage point or two
>>688561407
Change. Naturally the odds change from having a 25% chance to a 33% chance if I change.
>>688562513
>Implying this isn't post 9/11. It's not Home Alone 2 m9
>>688566708
66%
>>688570338
What's the fucking question?
I guess I solved it by figureing out you're a fucking tard.
>>688546392
>>688569792
>That janky ass writing
I ain't doin your homework for you
>>688548750
Mr. White should start cooking some meth.
>>688570962
>What's the fucking question
Found the tard
>>688570067
Incorrect
>>688564756
14/62=22.58%
>>688570902
Still no question in the post, even if it s obvious that is the question indeed..
>>688571052
us autists think alike
>>688556323
>>688562513
i'm actually having trouble with this :o
>>688570939
>you have 3 apples, one is safe, rest are poisoned
>you choose apple 2
chances it is safe are 1/3
>apple 1 gets eliminated
if you had to choose again now, you are right - you could pick the same apple again.
but since the chance of you picking a poisinous apple in the first place were 2/3 and there is only one other apple left, its chances of beeing poisined are 1/3
>>688571353
Guess it is how should the pirate captain distribute the coins?
Didn't make it myself.
>>688570338
Too bad for A. He has to propose 0, 50, 50, 0, 0 or he dies.
Well?
>>688548750
fan the hammer
ez
>>688570902
How the fuck am I supposed to know how they should distribute them. Clearly A is the superior, and there isn't a letter higher than A, so I'm not allowed to decide.
>>688571706
this thread is cancer
underaged newfags trying to math and logic
>>688571981
Because they have 46 chromosomes.
Or, for the more correct /pol/ answer. Because of the Jews.
>>688562513
0%.
You didn't have your boarding pass, and FDA requires you to have a boarding pass to board a plane.
You did not board.
>>688548750
he should shoot himself in the foot.
Ez peasy niggers, yall stupid
>>688571706
15 ezpz
>>688571981
they're basically same exact as everyone else, maybe the reason, but im not too sure
>>688562101
>>688565530
>>688566060
>>688566187
https://en.wikipedia.org/wiki/Monty_Hall_problem
Just to shed some light as to why switching is beneficial, and mathematically proven to be the correct choice.
It took my a while to begin understanding also because it feels absurd.
>>688571798
Look >>688564900
The question is only what probability the last one has to sit in his own seat.
First one NOT sitting in this guys seat: 99/100
Second one ...: 98/99
etc.
>>688572254
if you do not get on the plane, everyone else will have their own seat because your ass won't hog someone's spot, so the answer to the question would be 100%
>>688548750
Easy.
Considering Mr. Black is only 3/5s of a person and Mr. Gray is half black and therefore only 4/5s he should definitely shoot Mr. Gray first considering he is the largest target.
>>688548750
dodge the fucking bullet?
>is fast
>shootout
>wat do
Are we out of questions?
>>688562513
>>688571798
nvm i got it through induction.
p(x) is the chance for the last passager to have the correct seat in a plane with x passagers
p(1) = 1 obviously
p(2) = 1/2*1{i get it right the first time} + 1/2*0{i get 2's chair}
i now assume (A)(x > 1) p(x) = 1/2
i want to prove that (A)x p(x) -> p(x+1)
p(n+1) = 1/(n+1) * 1{i get it right} + 1/(n+1) * p(n){i get 2's chair and i force him into my situation} + 1/(n+1) * p(n-1){i get 3's chair and i force him into my situation} + ... + 1/(n+1) * p(2){i get n's chair} + 1/(n+1) * 0{i get (n+1)'s chair, so he's screwed}
p(n+1) = 1/(n+1) + (n-1)/(n+1)*1/2{induction hypothesis}
p(n+1) = (2+n-1)/(2*(n+1))
p(n+1) = (n+1)/(2*(n+1))
p(n+1) = 1/2
using the induction principle, we have (A)x>1 p(x) = 1/2
replace x with 100 and you have p(100) = 1/2
Nice problem, thanks for the fun
>>688573361
This
>>688559297
Is that a pepe?
>>688557470
Some kind of postulate that makes it impossible for the hypotenuse to be congruent to the adjacent sides of the right angle?
>>688572644
i think you missed the fact that if a person can find his chair, he will pick up his chair
>>688556945
They don't cross in the third dimension
>>688551716
This would lead to there still being an equal number between boys and grills . If we had 10 couples, 4 of wich would have a boy as a first child , 4 would have one girl and then one boy, and 2 would have 2 girls and one boy . We still have an equal number of children 8 girls and 8 boys
>>688563439
Electricity underground. Okay nigger
>>688573566
I mean an equilateral triangle has to have all 60 degree angles
>>688569792
Have fun with your complete elliptical integral of the second kind. https://en.wikipedia.org/wiki/Ellipse#Circumference
>>688573901
>Not having electricity underground.
What shit 3rd world country do you life in?
>>688565907
Lost
>>688568325
0%
25 is the abvious answer but since the results contain two instances of it, the chances turn to 50%. The correct answer changes on end result which is the winning condition. So 0% of guessed answers is correct.
>>688569078
2.
123 vs 456. If they're equal it must be in 789. Then of the light 3, weigh 1 vs 2. If they're equal, the 3rd ball is lightest
>>688574450
Wouldn't we need to know how many hated it in the first place? Or is it an infinite series issue where it changes such a small degree that it's negligable? Or is it just that /a/ is all shitposters?
>>688564756
6r=b
8b+14r=A
48+14=62
14/62=7/31
7/31=22.58%
>>688574450
day 1: 20%
day 2: 20*0,4+20=28
day 3: 28*0,4+20=31,2
day 4: 32,48
day 5: 32,992
day 6: 33,1968
Seems like we are approaching a limes, but it's too late to calculate.
>>688570338
Can work it out backwards:
If D E left he can take all the money himself (D=100, E=0)
If C D E left C needs to make a better offer than 0 to E so offer 1. (C=99, D=0, E=1) he will accept this otherwise he would get 0
If. B C D E left C needs to make better offer than 0 to D so offter 1 (B=99, C=0, D=1, E=0) he will accept this otherwise he would get 0
Finally A B C D E left A needs to make better offer than 0 to C and E being 1 they will accept this or get 0.
Final Offer A=98, B=0, C=1, D=0, E=1
>>688574450
the percent of haters starts at x%. Every day, it goes down by 20%. This is enough to solve the problem
Take f(d) be the perfect on haters on each day
by convention, f(0) is 100%, but it can be anything.
f(x) = f(x-1) * 80% (the other 20% converted)
using decomposition, you find out that
f(x) = f(0) * (80%)^x
by eventually, we take the limit when x -> infinity
you have lim f(x) = f(0) {constant} * 0.8 ^ inf
lim f(x) = f(0) * 0
lim f(x) = 0
However, f is strictly positive, so it never reaches that percent. Therefore, the eventual percent is undefined, but it tends towards 0.
This is assuming the 60% of the shitposters don't start hating it
>>688575549
kekèd
>>688575549
Get dry mum
>>688560199
For for a solution on standard 'planar' geometry, then either the right angle or congruence mark is inaccurate.
For a solution on non euclidean 'spherical' geometry, then there is a lack of additional right angle marks.
For a solution on non euclidean 'non spherical' geometry, then we should ask the old gods for guidance, because nothing we mark means anything.
>>688575599
I'm stupid and it's one hour after I wanted to go to sleep.
I know, not every day we add 20, since its only 20% of the hates, a set that changes in relation to the shitposter.
>>688558936
Coin 1: 50% chance
Coin 2: 25% chance
Coin 3: 12.5%chance
Coin 4: 6.25% chance
Coin 5: 3.125% chance
It is asking for the odds of you getting five heads in a row, not the last coin alone.
>>688560705
geometrical markings are a tool to 'draw to scale' when you physically cannot.
So yes, yes I do see 'drawn to scale' on that whiteboard.
>>688564756
Only one person got the right answer to this, so let me break it down.
In this case, we need to break the pattern into units - a single representative tile, in this case, which is best described as a parallelogram containing one Hexagon and two Red Triangles. Our goal is to calculate the area of each component, then divide appropriately. We are no longer considering the Plane, only the Tile (which will repeat endlessly, maintaining whatever ration we get).
We will assume the sides of the blue hexagon are of length 1. Units don't matter in this case. The area of the hexagon is easily calculated, then, as 2.59808 in the unimportant unit squared. The triangles, then, pose little issue. Recall that the area of an equilateral triangle is sqrt(3)/4 * L^2, where L is the side length.
We know the sides of the triangle are 1, which gives us an area of .43301 for one red triangle, but we have two. So our total red area is .86602.
Now, we need the ration of RED area to the TOTAL area, so let's calculate the total area, which is just red plus blue: .86602 + 2.59808 = 3.46410. We can verify this by considering a parallelogram and calculating that way (which demands splitting one red triangle into two right triangles, calculating their height, and doubling it to get the height of the parallelogram).
Finally, our ration of RED over TOTAL is .86602/3.46410, which is .24999855, or about .25.
Meaning the tile, and therefore the entire plane, is 25% red, 75% blue.
>>688575602
Aren't those that stop shitposting going back to the group of haters?
Do we have two groups (hater, shitposter) or three groups (hater, shitposter, former shitposter)?
>>688577074
Lapis Lasuli
>>688557470
19 _/2
Special right triangles, faggots
>>688561407
Assuming my goal is to 'win' the prize and by picking the door the prize is behind, I win...
Then regardless of which door I pick, each door has an equal chance of being correct. With 4 doors, each door is 25%. With 3 doors, each is 33.33%, with 2 each is 50% and if we were picking from 1 door, the door you didn't open (the one I picked) would be correct (but neither would I have the option to change).
Knowing this, if the door you opened, Door B, was guaranteed not to have a prize, then there is no change in % correct. If I had picked Door B and you opened another incorrect door, my % correct would have remained the same as the above example.
So my chances of winning are evenly split between 'Stay' and 'Change to Door C' and 'Change to Door D'
If I was given the chance to choose BOTH Doors C and D, then changing is the best choice.
>>688562513
Pretty sure its 1/100!
because the probability that you sit in their seat is 1/100, and decreases by one per passenger that enters.
1/9.332622e155
>>688576534
i did think of that, but i was too lazy to post it, it seems to easy if you ask me.
However, you're overthinking it. Each hexagon has 6 neighbouring triangles. we will divide each hexagon into 6 parts. We then hand out a share of the hexagon to each neighbouring triangle. This means every triangle that has 3 neighbouring hexagons receives 3 1/6 of that hexagon. Singe the triangles are red and the 1/6 of a hexagon blue{and of equal sizes} you conclude that the total area of red is n*A and the total area of blue is 3*n*A
Where n is the number of triangles and A is the area of a triangle.
Simple math and you get that the % of red is (n*A)/(4*n*A) * 100 = 1/4 * 100 = 25%
>>688577406
why?
>>688577074
rainbow dash is best poney ^.^
:3
>>688577440
There is also a 1/100 chance you sit in your own seat which balances it out.
Makes it overall 50%
>>688577113
it's not properly mentioned i'm afraid,but i think you're right
and i'm too lazy to redo the maths :(
>>688577597
>>688576405
No, he's asking for 5 heads in a row, when we already have four.
The formula is: (total event we want)/(event we already know)=(5 in a row)/(4 in a row)=0,03125/0,0625=0,5
