so 3 divided by 1/3 is 9, minus the 9 on the first equation then all you have left over is 1. So 1 is the answer to OP's problem. I hope this logic will help you in the future you blockhead.
>You are correct! You win the KFC secret recipe
I hope you morons end up with dish washing jobs, or just mopping. You can't handle 4th grade mathematics, the fact that you are out there driving scares me. You are both seriously retarded.
You guys are such retarded faggots. How can 3÷1/3 = 1 when 3÷3 =1 ?
The answer to the whole calculation is 1 because 3÷1/3=9 you Idiots. Or to explain it in retarded: You need 3 thirds to get to 1, so you need 9 thirds to get to 3.
You stupid monkeys.
>9 - 3 / (1/3) + 1
>= 9 -1 + 1
You understand division doesn't work that way, right?
Here, I'll break it down for your poorly educated ass.
When you are dividing a number, you're essentially asking the question "How many times does this number go into that number?"
So, 4 divided by 2 is asking "How many times does 2 go into 4?" The answer, of course, is 2.
So, right now we're asking "How many times does one third go into three?".
Let's take it step by step. Stick with me, dumbass.
How many times does 1/3 go into 1?
That's right, 3 times. Because three thirds make one. You follow that logic? Yes?
How many times does 1 go into 3?
That's right, 3 times.
So, if 1/3 goes into 1 three times, and 1 goes into 3 three times, how many times does 1/3 go into 3?
That's right! 9 times!
Congratulations on following basic math, you useless retard. Continue to dig ditches, as it is your only worthwhile contribution to this world.
you think you're so clever but really you're making a complete foll of yourself it is 6.75, explained much more concisely than you could right here:
seems it is you who will be wearing the name tag to work, mong.
You fell victim to one of the classic blunders!
The most famous is 'Never get involved in a land war in Asia,' but only slightly less well known is this: 'Never go in against an Anon when ego is on the line!'
The answer is 8.5 you fucking dolts!
The three digits in that equation are Positive Nine, Negative Nine and Positive One.
There is no addition and subtraction, only cumulation.
The cumulated total of positive nine, positive one and negative nine is positive one.
addition and substraction are the same thing you dimwit
No. PEMDAS mnemonics may be misleading when written this way, especially if the user is not aware that multiplication and division are of equal precedence, as are addition and subtraction.
Are you the same sort of dipshit that thinks Up and Down are completely different directions rather than movement on the same axis?
The equation is 9 - 9 + 1, not +9 -+9 ++1. Which would still be 1.
Are you the same dipshit who was arguing that 3 divided by 1/3 was 1? Because Christ, who does your taxes?
thank god i'm not american...
but even i know that Pemdas means
Multiplication/Division */ Note on how these are on the same level you fagets
Addition/Subtraction +- Same as above you mongotards
and otherwise left to right
the answer isn't 1 actually, as 1/3 is equal to .3 repeating. The answer to this equation depends on the amount of zeros following the decimal after 1. That number could be an infinite amount of zeros but lets say 1/3 = .3333333333 the last decimal place would be 1 so the answer would be 1.0000000001.
>But I'm smarter than a company dedicated to providing solutions for these equations, it can't be 1
>ITT: murican education system
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its 1 if youre a fucking normie reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
at any rate if you subtract .9r from 0 you will be left with a 1 somewhere down the line so that number in the equation can't possibly equal 0 because it cannot possibly equal .0r either.
First of all, what is point nine recurring? Well, think about writing down a fraction as a decimal. For example, you write a quarter as a decimal, you write 0.25. Other fractions can be a bit more troublesome. Trying to write a third as a fraction you get 0.33333333... It never ends. Instead of writing down an infinite number of 3s, it usually saves time to write down
which is said "zero point three recurring". Recurring means that instead of terminating, the decimal continues indefinitely. Similarly, point nine recurring is 0.999999...
Looking at this number, most people think it is a little bit less than 1. In fact they are the same. Let's take a look at why. Think about how we defined point three recurring above.
What does this mean in English? It means that three times a third is one, and three times point three recurring, which must be the same thing, is point nine recurring, so one and point nine recurring must be the same number. Feel free to use this explanation to look smarter than your friends if you ever get into an argument about recurring numbers.
If you are not convinced by this, perhaps you would like to think about it another way.
Translating this back to English, it means that nine times point nine recurring is nine, which is the same as nine times one, so point nine recurring and one must be the same.
I hope that at least one of these makes sense to you.
My god you cunts... - 9 + 1 = - 8... You treat the symbol in front of the number as though that's the value of the number, 1 - 2 + 1 doesn't equal 1 - 3, it's 1 + (-2 +1) = 1 - 1 = 0.
The answer to this equation implies that there is an end to infinity, which would mean that infinity isn't actually infinite and that there is an end to the so called number line. Two different numbers cannot possibly equal each other. That is an impossibility. The first part of this is only true if repeating numbers are actually infinite.
10 x 0.9r = 9.9r.
9 - 0.9r = 9.
Therefore: 10 x 0.9r - 0.9r = 9.
10 x 0.9r - 0.9r = 9 x 0.9r.
9 x 1 = 9.
Therefore: 10 x 0.9r - 0.9r = 9 x 1.
But: 10 x 0.9r - 0.9r = 9 x 0.9r
Therefore: 9 x 0.9r = 9 x 1.
people are retarded when it comes to math. or theyre just trolling. no when you have a number divided by a fraction you break that number into a fraction and do math... it looks like
9 - (3/1 over 1/3) + 1
9 - 9 +1
and to get 9 you multiply the 3s and the ones and it looks like 9/1... fucking morons. thats all there is to it.
according to pemdas the a comes before the s so the answer is actually -1...
Holy fuck, you people are retarded monkeys.
First of all, 1/3 is written as a fraction, which means it's a single number, so 3 / (1/3) is the first operation: And that is 9.
So you get:
9 - 9 + 1
Which is pretty fucking simple to finish off. But for the retarded monkeys, it's 1
There's a difference between an infinite number and a recursive number.
Recursive numbers occur primarily through a fault in the base ten counting module.
In base ten, one third is 0.3r.
In base twelve, one third is 0.4
nobody cares. its not a decimal question its a fraction question what 3/1 over 1/3. i'm surprised the people here are still arguing over this shit. either that or everbody is trolling everybody.
Oh, the trolls are definitely rolling around in the mud.
My point was just that there is a difference between an infinite number and a recursive one. Technically the space between all numbers is infinite. It's how we get the concept of Greater and Lesser infinities.
>Two different numbers cannot possibly equal each other. That is an impossibility.
True, but 1 and 0.9r aren't two different numbers. It's the same number written two ways. 1, 0.9r, 100/100, 0.1x10. These are all different ways of writing the exact same number.
Stop smoking the wacky-tobaccy, anon.
Answer... depends on how you read 1/3.
If you read it as a fraction such that it is 1 / 3 = 0.333, then the answer is 1.
If you read it as an operation such that 1/3 = 1 divided by 3, then you read left to right so you get (3 / 1) / 3 which is 1, and the answer is 9.
When you divide by a fraction, you make the whole number a fraction and multiply by the reciprocal of the fraction you are dividing it by.
3 / (1/3) is equal to (3/1) * (3/1)
(3/1) * (3/1) = (9/1)
(9/1) = 9
PEMDAS doesn't put multiplication before division or addition before subtraction. the M and D are equal, as are the A and S. You just do it left to right. The P and E are always first, then you do the M and D at the same time (left to right), then the A and S (left to right).
If you have 5 - 4 + 6, then you would simplify that to 1 + 6, not 5 - 10, because you move left to right.
9 - 3 / (1/3) + 1 =
9 - ((3/1) * (3/1)) + 1 =
9 - ((9/1)) + 1 =
9 - 9 + 1 =
0 + 1 = 1
You're a retard.
They already have a divide symbol in the equation, and the placement and writing of the 1/3 is clearly fractional.
It's clearly supposed to read nine minus three divided by one third plus one. Not nine minus three divided by one divided by three plus one.
You just added brackets where there are none to prove your point, so take them out as those brackets do not exists you little fuckwit
It's not trumping it. It IS the whole BODMAS/PEDMAS/BIDMAS thing.
The D and M are equal, as is the A and S. You work left to right.
10 * 2 / 2 =
20 / 2 = 10
20 / 2 * 4 =
10 * 4 = 40
Close, but when you divide a fraction you multiply its reciprocal, meaning you swap the numerator and denominator.
3 / (1/3) =
(3/1) * (3/1) =
(9/1) = 9
9 - 9 = 0
0 + 1 = 1
So, 9 - 3 ÷ 1/3 + 1
= 9 - (3 ÷ 1/3) + 1
= 9 - 1 + 1
If you aren't a retarted american you know that you do divisions before add. and sub. I can't tell if you are all trolling or genuinely retarded
>3÷1/3 = 1
Oh please. The oc pic stated the fraction as it's supposed to be. You interpreted it as (3÷1)/3.
>"you fucking gypsy"
Nigga wat? Do you know how fractions work?
Yeah man. Look how the fraction is vertical. It just doesn't make sense to interact with that before resolving it. Although this is a special case - just take reciprocal then multiply for 3*3.
Quit being a bunch of lazy fucking cock suckers and put the parenthesis in the equation that defines the order of operation, until then it is solved from left to right and the fucking answer is 3
>Add andsubtract last
What you are thinking of when you say it = 9 is 3 multiplied by 1/3.
I have visions of killing animals What is wrong with me /b/ ?
i again underestimated how stupid the average anon is. thanks for reminding me, op